4(x^2-7)+27=12x^2

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Solution for 4(x^2-7)+27=12x^2 equation: 



4(x^2-7)+27=12x^2

We move all terms to the left:

4(x^2-7)+27-(12x^2)=0

determiningTheFunctionDomain
-12x^2+4(x^2-7)+27=0

We multiply parentheses

-12x^2+4x^2-28+27=0

We add all the numbers together, and all the variables

-8x^2-1=0

a = -8; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-8)·(-1)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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